Question

1.Tentukan Ph larutan HCl 0,1 molar

Answer 1

Diket:[H+]=1.10pngkt-1
ph=-log(1.10pngkt -1)
=1

Answer 2

HCl = H⁺ + Cl⁻
[H⁺] = koefisien H / koefisien HCl x 0.1
[H⁺] = 1/1 x  0.1 = 0.1
[H⁺] = 1 x 10 ⁻¹

pH = - log [H⁺]
pH = - log 1 x 10⁻¹
pH = 1