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Lp = 2 (360 + 270 + 300)
= 2 (930)
= 1860 cm²
L 1 karton = 20 x 31 = 620 cm²
Byk karton yg dibutuhkan = 1860 / 620 = 3
2. V = s³
125 = s³
5 = s
Lp = 6s²
= 6 . 5²
= 6 . 25
= 150 cm²
= 620 cm²
Luas Permukaan Balok = 2 ( pl + pt + lt )
= 2 ( 20x18 + 20x15 + 18x15 )
= 2 ( 360 + 300 + 270 )
= 2 ( 930 )
= 1860 cm²
Kertas karton yang dibutuhkan
= 1860 : 620
= 3 kertas karton
2.) V = s³
125 = s³
s = ∛125
s = 5
Luas Permukaan
= 6 x s²
= 6 x 5²
= 6 x 25
= 150 cm²