1)Rozłóż na czynniki dany wielomian: x4-6x3+9x2
2) Zapisz w postaci iloczynu trzech czynników wyraznie: a+a4
x⁴-6x³+9x²=
x²(x²-6x+9)=
x²(x²-3x-3x+9)=
x²(x(x-3)-3(x-3))=
x²(x-3)(x-3)=
x²(x-3)²
a(a+1)(a²-a+1)
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x⁴-6x³+9x²=
x²(x²-6x+9)=
x²(x²-3x-3x+9)=
x²(x(x-3)-3(x-3))=
x²(x-3)(x-3)=
x²(x-3)²
a(a+1)(a²-a+1)