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2. mCaCO3= 40u + 12u + 16u*3= 100u
O% = mO/mCaCO3=48u/100u*100%= 48% :)
mCaCO₃= 40u+12u+3*16u=100u
mO= 3*16u= 48u
100u------- 100%
48u -------- x
x= 48%