1.Oblicz,ile gramów tlenku węgla(IV) zostanie wyemitowane do atmosfery podczas spalania 10kg metanu.
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mCH₄=16u
mCO₂=44u
CH₄ + 2 O₂ ---> CO₂ + 2H₂O
16g metanu ----- 44g CO₂
10000g metanu ---- x g CO₂
x = 27500g CO₂