1.Oblicz pole trapezu.
a)a= 4 cm
b=2,6 cm
h=2 cm
P=.................
b)a=4 cm
b= 3 cm
h= 2 cm
P=............
c) a =3 cm
b= 2 cm
h = 3 cm
P=..................
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a)a= 4 cm
b=2,6 cm
h=2 cm
P =
P =
dwójki się skrócą
zostaje
P = 4 + 2,6
P= 6 , 6 cm
b)
a=4 cm
b= 3 cm
h= 2 cm
P=
P= 4 + 3 = 7 cm
c.
a =3 cm
b= 2 cm
h = 3 cm
P=
a)a= 4 cm
b=2,6 cm
h=2 cm
P =![\frac{a+b }{2}*h \frac{a+b }{2}*h](https://tex.z-dn.net/?f=%5Cfrac%7Ba%2Bb+%7D%7B2%7D%2Ah)
P =![\frac{4 + 2,6 }{2} *2 \frac{4 + 2,6 }{2} *2](https://tex.z-dn.net/?f=%5Cfrac%7B4+%2B+2%2C6+%7D%7B2%7D+%2A2)
dwójki się skrócą
zostaje
P = 4 + 2,6
P= 6 , 6 cm
b)
a=4 cm
b= 3 cm
h= 2 cm
P=![\frac{4+3}{2} *2 \frac{4+3}{2} *2](https://tex.z-dn.net/?f=%5Cfrac%7B4%2B3%7D%7B2%7D+%2A2)
P= 4 + 3 = 7 cm
c.
a =3 cm
b= 2 cm
h = 3 cm
P=![\frac{3+2}{2}*2 \frac{3+2}{2}*2](https://tex.z-dn.net/?f=%5Cfrac%7B3%2B2%7D%7B2%7D%2A2)