1)Oblicz pole całkowite graniastoslupa prawidlowego trojkatnego w ktorym krawedz ma 12 cm.
2)oblicz pole clakowite szescianu o krawedzi 2 pierwiastek z 7.
SPeed daje naj
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1. a=12cm
Pc=2a^2+3*a^2√3/4=2*12^2+3/4*12^2√3=288+108√3cm²
2. a=2√7
Pc=6a^2=6*(2√7)^2=6*28=168cm²