1.Oblicz mase:
a) 3 moli ołowiu
b) 0,5 mola wapnia
c) 5 moli węglanu potasu
d) 2 moli kwasu siarkowego vi (6)
2.Obilcz ile moli stanowi:
a)3,2g siarki
b)6g wody
c)12g magnezu
d) 12,6 kwasu azotowego v
e) 11g tlenku węgla iv (4)
3.Oblicz skład procentowy tlenku fosforu v
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1. Mpb=207 g/mol
1mol - 207g
3mol- x
x=621g
Mca=40g/mol
1mol- 40g
0,5mol - x
x=20g
Mk2co3=2*39g/mol+12g/mol+48g/mol=138g/mol
1mol - 138g
5mol - x
x=690g
Mh2so4=2g/mol+32g/mol+64g/mol=98g/mol
1mol- 98g
2mol-x
x=196g
2.ms=3,2g
Ms=32g/mol
1mol-32g
x-3,2g
x=0,1mol
mh20=6g
Mh2o=18g/mol
1mol-18g
x-6g
x=0,33mol
mmg=12g
Mmg=24g/mol
1mol-24g
x-12g
x=0,5mol
mhno3=12,6g
Mhno3=63g/mol
1mol-63g
x=12,6g
x=0,2mol
mco2=11g
Mco2=44g/mol
1mol-44g
x-11g
x=0,25mol
3.Mp2o5=2*31g/mol+5*16g/mol=142g/mol
142g/mol-100%
90g/mol-x
x=90g*100%/142g=63,38%
%mo=63,38%
%mp=100%-63,38%=36,62%