Question

1Oblicz masę cząsteczkową nastepujących związków:NaOH,Fe(OH)2,Al(OH)3,K2CO3,MgSO3,Li3PO4,Fe(PO4)2,C2H6,C2H6O2N5

Answer 1

mNaOH = 23u+16u+1u = 40u

mFe(OH)2 = 56u+(16u+1u)*2 = 56u+34u = 90u

mAl(OH)3 = 27u+(16u+1u)*3 = 27u+51u = 78u

mK2CO3 = 2*39u+12u+3*16u = 78u+12u+48u = 138u

mMgSO3 = 24u+32u+3*16u = 104u

mLi3PO4 = 3*7u+31u+4*16u = 116u

mFe(PO4)2 = 56u+(31u+4*16u)*2 = 56u+95u*2=246u

mC2H6 = 2*12u+6*1u = 30u

mC2H6O2N5 = 2*12u+6*1u+2*16u+5*14u = 132u

Answer 2

1. 23u+16u+1u = 40u

2. 56u+(16u+1u)*2 = 56u+34u = 90u

3. 27u+(16u+1u)*3 = 27u+51u = 78u

4. 2*39u+12u+3*16u = 78u+12u+48u = 138u

5. 24u+32u+3*16u = 104u

6. 3*7u+31u+4*16u = 116u

7. 56u+(31u+4*16u)*2 = 56u+95u*2=246u

8. 2*12u+6*1u = 30u

9. 2*12u+6*1u+2*16u+5*14u = 132u

Prosta praca z układem okresowym ;)