Odpowiedź:
1.
[H^(+)]=10^(-pH)
[H^(+)]=10^(-5)mol/dm3
2.
pH=-log[H^(+)]=-log(10^(-8))=8 zasadowy
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Odpowiedź:
1.
[H^(+)]=10^(-pH)
[H^(+)]=10^(-5)mol/dm3
2.
pH=-log[H^(+)]=-log(10^(-8))=8 zasadowy