1.ile gramów 20%kwasu octowego przereaguje z 32,2g cunku?
mZn=65u
mCH3COOH=60u
2CH3COOH + Zn---->(CH3COO)2Zn + H2
120g CH3COOH---------65g Zn
xg CH3COOH----------32,2g Zn
x = 59,4g CH3COOH
Z def. stęż. procent.
20g kwasu------100g roztworu
59,4g kwasu-----xg roztworu
x = 297g kwasu octowego
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mZn=65u
mCH3COOH=60u
2CH3COOH + Zn---->(CH3COO)2Zn + H2
120g CH3COOH---------65g Zn
xg CH3COOH----------32,2g Zn
x = 59,4g CH3COOH
Z def. stęż. procent.
20g kwasu------100g roztworu
59,4g kwasu-----xg roztworu
x = 297g kwasu octowego