1.ile cząsteczek znajduje się w 34g. NH3?
2. oblicz masę 11,2 dm3 SO3?
1. mNH3= 17g 17g --- 6,02 * 10²³ cz.34g --- x cz. x= 12,04 * 10²³ cz. 2. mSO3= 32g + 3* 16g = 32g + 48g = 80g 80g --- 22,4dm3xg ---- 11,2dm3x= 40g
Pozdrawiam, kate66 ;)
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
1.
mNH3= 17g
17g --- 6,02 * 10²³ cz.
34g --- x cz.
x= 12,04 * 10²³ cz.
2.
mSO3= 32g + 3* 16g = 32g + 48g = 80g
80g --- 22,4dm3
xg ---- 11,2dm3
x= 40g
Pozdrawiam, kate66 ;)