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=(3xy(x−2))(5x+1)
= (3xy(x−2))(5x)+(3xy(x−2))(1)
= - + - 6xy
= - + 6xy
2) (3p+7)(5−2p)
= (3p+7)[(5+(−2p)]
= (3p)(5)+(3p)(−2p)+(7)(5)+(7)(−2p)
= 15p− +35−14p
= +p+35
Sorry jawaban yang awal itu kepencet pas ngerjain soal