Question

1.diketahui fungsi f(x) = 2x-1 dan g(x) = 3x nilai dari ( g o f ) (2) adalah

2.diketahui fungsi f(x) = 3x-2 dan g(x) = 2x^ - x .Rumus ( g o f ) (x) adalah

Answer 1

Matematika

Nomor 1

(gof) (x) = g(f(x))

= 3f(x)

= 3(2x - 1)

(gof) (2) = 3(2(2) - 1)

= 3(3)

= 9

Nomor 2

(gof) (x) = g(f(x))

= 2f(x)² - f(x)

= 2(3x - 2)² - (3x - 2)

= 2(9x² - 12x + 4) - 3x + 2

= 18x² - 24x + 8 - 3x + 2

= 18x² - 27x + 10

Answer 2

1. f(x) = 2x-1, g(x) = 3x

(g o f)(2) = g(f(2))

                  = g(2.2-1)

(g o f)(2) = g(3) = 3.3 = 9

2. (g o f)(x) = 2(3x-2)²-(3x-2)

                 = (3x-2).(2(3x-2) - 1)

                  = (3x-2)(6x-5)

(g o f)(x) = 18x²-27x+10