wyznacz sumę 2/1*3+2/3*5+2/5*7+....+2/19*21=
[2n(2n+3)+2]/[(2n+1)(2n+3)]=[(2n+1)(2n+2)]/[(2n+1)(2n+3)]=(2n+2)/(2n+3)
L=P c.n.d.
dla powyzszej sumy
mamy: 19=2n-1
2n=20
n=10
S=20/21
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[2n(2n+3)+2]/[(2n+1)(2n+3)]=[(2n+1)(2n+2)]/[(2n+1)(2n+3)]=(2n+2)/(2n+3)
L=P c.n.d.
dla powyzszej sumy
mamy: 19=2n-1
2n=20
n=10
S=20/21