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y=5/3
m₁=0
syarat garis sejajar m₁=₁m₂=0
pers grs
y-y₁=m(x-x₁)
y-2=0(x-3)
y-2=0
y=2
2x + y - 4 = 0
y=-2x+4
m₁=-2
syarat gris yg tgak lurus
m₁x m₂=-1
-2m₂= -1
m₂= 1/2
y-y₁=m(x-x₁)
y-0=1/2(x-0)
y=1/2x atau x-2y=0