Odpowiedź:
[tex]\Large\boxed{P=\dfrac{1}{6}}[/tex]
Szczegółowe wyjaśnienie:
[tex]P=\dfrac{3}{20}+\dfrac{2}{20}\cdot \dfrac{3}{19}+\dfrac{2}{20}\cdot\dfrac{1}{19}\cdot\dfrac{3}{18}=\\[5]\dfrac{3}{20}\cdot\left(1+\dfrac{2}{19}+\dfrac{2}{19\cdot18}\right)=\\[5]\dfrac{3}{20}\cdot\left(1+\dfrac{2}{19}\cdot\left(1+\dfrac{1}{18}\right)\right)=\\[5]\dfrac{3}{20}\cdot\left(1+\dfrac{2}{{\not}19}\cdot\dfrac{{\not}19}{18}\right)=\\[5]\dfrac{3}{20}\cdot\left(1+\dfrac{2}{18}\right)=\\[5]\dfrac{3}{{\not}20}\cdot\dfrac{{\not}20}{18}=\dfrac{1}{6}[/tex]
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Odpowiedź:
[tex]\Large\boxed{P=\dfrac{1}{6}}[/tex]
Szczegółowe wyjaśnienie:
[tex]P=\dfrac{3}{20}+\dfrac{2}{20}\cdot \dfrac{3}{19}+\dfrac{2}{20}\cdot\dfrac{1}{19}\cdot\dfrac{3}{18}=\\[5]\dfrac{3}{20}\cdot\left(1+\dfrac{2}{19}+\dfrac{2}{19\cdot18}\right)=\\[5]\dfrac{3}{20}\cdot\left(1+\dfrac{2}{19}\cdot\left(1+\dfrac{1}{18}\right)\right)=\\[5]\dfrac{3}{20}\cdot\left(1+\dfrac{2}{{\not}19}\cdot\dfrac{{\not}19}{18}\right)=\\[5]\dfrac{3}{20}\cdot\left(1+\dfrac{2}{18}\right)=\\[5]\dfrac{3}{{\not}20}\cdot\dfrac{{\not}20}{18}=\dfrac{1}{6}[/tex]