September 2018 1 25 Report

Oblicz :

a) 22^{6} * (-2)^ 3 : (-2)^8

b) \frac{5^7 * (-5)^2^4}{5^1^3 * 5^1^8}

c)\frac{(-7)^1^0}{7^8 * (-7)}

d) (-\frac{1}{4})^5 : 0,25^2

e) (-0,1)^3 * 0,1 ^4:0,1^2

f) \frac{(-0,2)^3 * 0,2^4 * (-0,2)^4}{-(-0,2^4 * 0,2^6)}

Jest to temat Potęgi. Matematyka 2 gimnazjum zadanie 11/17 nowa podstawa ;) Z góry dzięki za pomoc. Proszę z obliczeniami.


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