Question

oblicz:

a) (2¼)do -½potegi

b) log₆9+log₆4

c) log₁₂1/9+log₁₂1/16

Answer 1

 

Answer 2

a)

(2¼)⁻¹/² = (9/4)⁻¹/² = (4/9)¹/² = √(4/9) = 2/3

b)

log₆9 + log₆4 = log₆(9·4) = log₆36 = 2,  bo 6² = 36

c)

log₁₂(1/9) + log₁₂(1/16) = log₁₂(1/9 · 1/16) = log₁₂(1/144) = -2,  bo 12⁻² = 1/144

 

 

log_a x + loga y = log_a (x·y)