Zapisz w postaci iloczynu:a) (27x^3-8)=b) 1/16 x^2-4)=
c) 4- (a+5)^2
a) (3x)³ - 2³ = (3x-2)(9x²+12x+4)
b) (¼x)² - 2² = (¼-2)(¼+2)
c) 2² - (a+5)² = (2-a-5)(2+a+5) = -(a+3)(a+7)
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a) (3x)³ - 2³ = (3x-2)(9x²+12x+4)
b) (¼x)² - 2² = (¼-2)(¼+2)
c) 2² - (a+5)² = (2-a-5)(2+a+5) = -(a+3)(a+7)