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a)πr²= 0,04π dm²/:π
r²=0,04
r=0,2dm
b)πr²= π km²/:π
r²=1
r=1km
c) πr²= 9/16 π mm²/:π
r²=9/16
r=3/4mm
a.
0,04π dm²=πr²
0,04=r²
0,2=r
b.
π km²=πr²
1=r²
1=r
c.
9/16 π mm²=πr²
9/16=r²
¾=r
r²=0,04; bo wzór na pole koła to πr²
0,2=r
b)
πr²=1π²
r²=1
r=1
c)
πr²=9/16πr²
r²=9/16
r=3/4