Question

Oblibcz

a) [(3 1/2)^-1 - 14^-1]^-2

b) [(2 1/2)^-2 - (1 9/16)^-1]^-1

c) (0,1^-2 - 0,25^-1)^-1

d) [0,2^-1+(0,3)^-1]^-2

Bardzo bym prosiła o to żeby nie pisać samego wyniku bo nie wiem jakto zrobić a chciałabym wiedzieć jak to zrobiliście

Answer 1

a) [(3 1/2)^-1-14^-1]^-2=

=[(7/2)^-1-14^-1]^-2=

=[(2/7)^-1-(1/14)^-1]^-2=

=(2/7-1/14)^-2=

=(4/14-1/14)^-2=

=(3/14)^-2=

=(14/3)^2=

=196/9=

=21 7/9

 

b) [(2 1/2)^-2 - (1 9/16)^-1]^-1

=[(5/2)^-2-(25/16)^-1]^-1=

=[(2/5)^2-(16/25)^1)^-1=

=(4/25-16/25)^-1=

=(-12/25)^-1=

=(-25/12)^1=

=-25/12=

=-2 1/12

c) (0,1^-2 - 0,25^-1)^-1=

=[(1/10)^-2-(1/4)^-1]^-1=

=(10^2-4^1)^-1=

=(100-4)^-1=

=96^-1=

=(1/96)^1=

=1/96 

 

d) [0,2^-1+(0,3)^-1]^-2=

=[)1/5)^-1+(3/10)^-1]^-2=

=[5^1+(10/3)^1]^-2=

=(5+10/3)^-2=

=(15/3+10/3)^-2=

=(25/3)^-2=

=9/625=

=0,0144