a)-6i1/2:5i1/5+2i1/4:(-1i1/5)= b)(1i3/10-2i4/5):(1i3/4-3i5/6)= c)(1i1/4-3i5/6)*(2i3/5-1i3/4)= d)(3i1.... Question from @Andrea12345

September 2018 1 15 Report

a)-6i1/2:5i1/5+2i1/4:(-1i1/5)= b)(1i3/10-2i4/5):(1i3/4-3i5/6)= c)(1i1/4-3i5/6)*(2i3/5-1i3/4)= d)(3i1/2-5i3/4)*(-1i3/5+23/30)*(1i1/6-3i13/15)= POMOCY !!!!!

Roma

$-6\frac{1}{2} \ : \ 5\frac{1}{5} + 2\frac{1}{4} \ : \ (-1\frac{1}{5}) = -\frac{13}{2} \ : \ \frac{26}{5} + \frac{9}{4} \ : \ (-\frac{6}{5}) = -\frac{13}{2} \cdot \frac{5}{26} + \frac{9}{4} \cdot (-\frac{5}{6})=$

$= -\frac{5}{4} -\frac{15}{8} = -\frac{10}{8} -\frac{15}{8}= -\frac{25}{8} = -3\frac{1}{8}$

$(1\frac{3}{10} - 2\frac{4}{5}) \ : \ (1\frac{3}{4} - 3\frac{5}{6}) = (1\frac{3}{10} - 2\frac{8}{10}) \ : \ (1\frac{9}{12} - 3\frac{10}{12}) = - 1\frac{5}{10} \ : \ (- 2\frac{1}{12}) =$

$= - 1\frac{1}{2} \ : \ (-\frac{25}{12}) = - \frac{3}{2} \cdot (-\frac{12}{25}) = \frac{18}{25}$

$(1\frac{1}{4} - 3\frac{5}{6}) \cdot (2\frac{3}{5} - 1\frac{3}{4}) = (1\frac{3}{12} - 3\frac{10}{12}) \cdot (2\frac{12}{20} - 1\frac{15}{20}) = - 2\frac{7}{12} \cdot \frac{17}{20} =$

$= -\frac{31}{12} \cdot \frac{17}{20} = -\frac{527}{240} = - 2\frac{47}{240}$

$(3\frac{1}{2}-5\frac{3}{4}) \cdot (-1\frac{3}{5}+\frac{23}{30}) \cdot (1\frac{1}{6}-3\frac{13}{15})= (3\frac{2}{4}-5\frac{3}{4}) \cdot (-1\frac{18}{30}+\frac{23}{30}) \cdot (1\frac{5}{30}-3\frac{26}{30})=$

$=-2\frac{1}{4} \cdot (-\frac{25}{30}) \cdot (-2\frac{21}{30})=-\frac{9}{4} \cdot (-\frac{5}{6}) \cdot (-2\frac{7}{10})=-\frac{9}{4} \cdot (-\frac{5}{6}) \cdot (-\frac{27}{10})=$