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Verified answer
VektorC' = A + T1
C' = (-2, 4) + (5, 8)
C' = (3, 12)
Dan
C' = B + T2
C' = (6, 8) + (a, b)
C' = (6 + a, 8 + b)
Substitusi
C' = C'
(3, 12) = (6 + a, 8 + b)
Maka berlaku
6 + a = 3
a = -3
Dan
8 + b = 12
b = 4
Sehingga matriks T2 (-3, 4)