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Verified answer
◾ Materi : Termodinamika◾ Sub materi : Mesin Kerja
◾ Mapel : Fisika
◾ Keyword : Termodinamika, Mesin Kerja, Carnot
Diketahui :
Tt = 468 K
Tr = 312 K
Qt = 6000 J
Ditanya :
Qr = ?
Penyelesaian :
η = Qt - Qr / Qt
Tt - Tr / Tt = Qt - Qr / Qt
468 - 312 / 468 = 6000 - Qr / 6000
156/468 = 6000 - Qr / 6000
156(6000) = 468(6000 - Qr)
936.000 = 2.808.000 - 468Qr
468Qr = 1.872.000
Qr = 4000 J
Jadi, besarnya kalor lepasan mesin tsb adalah 4000 J
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-vin