Penjelasan dengan langkah-langkah:
BD/sin A = AD/sin B
BD/sin 45° = 2/sin 30°
BD = (1/2 √2 . 2)/(1/2)
BD = 2 √2 cm
BD/sin C = BC/sin BDC
sin C = (sin 60° . 2 √2)/4
sin C = (1/2 √3 . 2 √2)/4
sin C = 1/4 √6
Kelas 11
Pelajaran Matematika
Bab Trigonometri Lanjut
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Penjelasan dengan langkah-langkah:
BD/sin A = AD/sin B
BD/sin 45° = 2/sin 30°
BD = (1/2 √2 . 2)/(1/2)
BD = 2 √2 cm
BD/sin C = BC/sin BDC
sin C = (sin 60° . 2 √2)/4
sin C = (1/2 √3 . 2 √2)/4
sin C = 1/4 √6
Kelas 11
Pelajaran Matematika
Bab Trigonometri Lanjut