Question

1.(2x-1)² – (y-2)² = 2(x+3)² - 0,5(1-y) - tu jest podzielić prze dwa;)
2
8x + 2y+6=0


2.(x-y)(x+y)= (x-2)²-(y+3)²
3x+4y=3,2

Answer 1

1.(2x-1)² – (y-2)² = 2(x+3)² - 0,5(1-y) * ½
4x²+1-y²+4=2(x²+9)-0,5+0,5y*½
4x²+1-y²-4=2x²+18-0,5+0,5y*½ /*2
8x²+2-2y²-8=4x²+36-1+1*1
8x²-6-2y²=4x²+36

2.
8x + 2y+6=0 /-6
8x+2y=-6 /:2
4x+y= -3 /-4x
y=-3 - 4x

3.
(x-y)(x+y)= (x-2)²-(y+3)²
x²+xy-xy-y²= x²+4 - y² + 9
x²-y²=x²-y²+13

4.
3x+4y=3,2 /-3x
4y=3,2-3x /:4
y=0,8 - 0,75x