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Pomóżcie mi potrzebne mi to na 29 listopada
og 10
log 1000
log 0.1
log ₀.₁ 1000
log ₅ 1/125
log⅕ ⁴√5
log√₃ 27
log³√₆ 6
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wzór ogólny logab=c, ado potegi c =b , więc:
log₁₀10=x
10 do potegi x=10
x=1
log₁₀1000=x
10 do potegi x= 1000
x=3
log₁₀0,1=x
10 do potegi x=0,1
x=-1
log₀,₁1000=x
0,1 do potegi x =1000
(¹/₁₀) do potegi x=(¹/₁₀)⁻³
x=-3
log₅¹/₁₂₅ = x
5 do potegi x=(⅕)³
5 do potegi x=5⁻³
x=-3
log⅕ ⁴√5=x
⅕ do potegi x = ⁴√5
⅕ do potegi x= ⅕ do potegi -¼
x=-¼
log√₃ 27=x
√3 do potegi x =27
√3 do potegi x= 3³
3 do potegi ½x= 3³
½x=3
x=1,5
log³√₆ 6=x
∛6 do potegi x = 6
6 do potegi ⅓x= 6
⅓x= 1
x=3