11u*x%+12u*(1oo%-x)
_____________________ =10,81u
100%
pomocy...to na jutro:(
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11u*x%+12u*(1oo%-x)
_____________________ =10,81u
100%
pomocy...to na jutro:(
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Wg mnie liczby masowe powinny wynosić odpowiednio 10 i 11.
10u*x%+11u*(1oo%-x)
_____________________ =10,81u
100%
10*x+11*(1oo-x) = 1081
10*x+1100-11x = 1081
x = 91
¹¹B = 91%
¹²B = 19%