ODEJMOWANIE UŁAMKÓW ZWYKŁYCH
1i1/9 - 4/7 =
2i1/2-1i3/5 =
24i5/6 - 12i2/3 =
3i7/10 - 1i4/15 =
3i58 - 5/6 =
34i7/12 - 5i3/4 - 2i5/6 =
4i4/5 - 2i5/6 =
5i2/7 - 3i2/3 =
10i1/4 - 5i3/7 =
8i7/15 - 6i3/4 =
3i5/11 - 2i4/5 =
6i29/30 - 4i34/90 =
23 - 3i4/11 =
bardzo proszę o pomoc bo ja nie mam pojecia w tym żadnego
z góry bardzo dziękuje wszystkim tym którzy mi pomogą
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2i1/2-1i3/5 = 9/10
24i5/6 - 12i2/3 = 12 i 1/6
3i7/10 - 1i4/15 = 2 i 13/30
3i58 - 5/6 = 2 i 28/58
34i7/12 - 5i3/4 - 2i5/6 = 12
4i4/5 - 2i5/6 = 1 i 29/30
5i2/7 - 3i2/3 = 1 i 13/21
10i1/4 - 5i3/7 = 4 i 23/28
8i7/15 - 6i3/4 =4 i 1/12
3i5/11 - 2i4/5 = 36/55
6i29/30 - 4i34/90 = 2 i 53/90
23 - 3i4/11 = 19 i 7/11