Oblicz.
a)4²*(1/4)²-(1/5)³*5³=
b)(1/7)²*14²-10⁵+(1/5)⁵=
c)35²:(-7)²+(-6)³:(-2)³=
d)(-1/9)²:(1/72)²-(-1/36)³:(1/108)³=
PLSS prosze zeby ktos w tym pomógł za dobre rozwiozanie dam 5 gwiazdek.
Wyniki;
a)0
b)-28
c)52
d)91
Prosze o rozwiozanie.
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a) (4/1)² * (1/4)² - (1/5)³ * (5/1)³ = 1-1 = 0 [bo tam sie poskraca]
b) (1/7)² * (14/1)² - (10/1)⁵ * (1/5)⁵ = 2² - 2⁵ = 4-32 = -28