1.zapisz w postaci dziesętnej-
829/100
2.uzupełnij
0,3cm= mm
0,4m= cm
1,3kg= dag
1725m = km
5t 78kg= t
1.
829/100=8,29
2
0,3cm= 3 mm
0,4m= 40 cm
1,3kg= 130 dag
1725m = 1,725 km
5t 78kg = 5,078t
8,29
2.
0,3cm=3mm
0,4m=40cm
1725m=1,725km
5t 78kg=5,078t
liczę na naj:)
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1.
829/100=8,29
2
0,3cm= 3 mm
0,4m= 40 cm
1,3kg= 130 dag
1725m = 1,725 km
5t 78kg = 5,078t
1.
8,29
2.
0,3cm=3mm
0,4m=40cm
1,3kg130dag1725m=1,725km
5t 78kg=5,078t
liczę na naj:)