100 ml ch3cooh 0, 2 m dicampur 100 ml naoh 0, 1 m, hitung a)ph masing masing
b)ph campuran
b)ph campuran
Hanamiwa
Ch3cooh +naoh=» ch3coona+ h20 Na 0,2.100=20 20 Nr -20 -20 20 Ns 0 0 20 A.) ch3cooh =» ch3coo- + h+ 0,2 0,2 0,2 Ph ch3cooh =-log 2.10^-1=1-log 2 Naoh=» Na+ +oh- 0,1 0,1 0,1 Poh naoh=-log1.10^-1=1 Ph=» 14-1=13 B.) M=n/vt=20/200=0,025=2,5.10^-2 oh-=
=5.10^-6 Poh =6-log5 Ph =8+log5
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Thanks 2
Hogoo
Maaf tadi lupa kb nya 10^-5 ya