1. Zapisz w postaci jednej potęgi. - a) (63)4. (62)3 = d) (58): (56)8 = b) (72)5. (75)2 = e) (0,64) .... Question from @chmieljulia518

June 2022 2 12 Report

1. Zapisz w postaci jednej potęgi. - a) (63)4. (62)3 = d) (58): (56)8 = b) (72)5. (75)2 = e) (0,64) : (0,67)² = 3 212 10 C) f) (13)*)*: (03))"
WSZYTKO NA ZDJ!!!!!

10days

Zapisane w załączniku, miłego wieczoru :P

4 votes Thanks 5

xamiiix pomożesz mi w tym zadaniu: https://brainly.pl/zadanie/21628609 ??? będę mega wdzięczna dam naj

basetla

$a) \ (6^{3})^4} \cdot(6^{2})^{3} = 6^{12}\cdot6^{6} = 6^{18}\\\\b) \ (7^{2})^{5}\cdot(7^{5})^{2} = 7^{10}\cdot7^{10} = 7^{20}\\\\c) \ ((\frac{1}{3})^{3})^{3}\cdot((\frac{1}{3})^{2})^{2}=(\frac{1}{3})^{9}\cdot(\frac{1}{3})^{4} = (\frac{1}{3})^{13}$

$d) \ (5^{8})^{7}:(5^{6})^{8} = 5^{56}:5^{48} = 5^{8}\\\\e) \ (0,6^{4})^{5}:(0,6^{7})^{2} = 0,6^{20}:0,6^{14} = 0,6^{6}\\\\f) \ ((\frac{5}{7})^{3})^{8}:((\frac{5}{7})^{2})^{10} = (\frac{5}{7})^{24}:(\frac{5}{7})^{20} = (\frac{5}{7})^{4}$

Wyjaśnienie:

Z własności potęg:

$(a^{m})^{n} =a^{m\cdot n}\\\\a^{m}\cdot a^{n} =a^{m+n}\\\\a^{m}:a^{n} = a^{m-n}$

1 votes Thanks 0

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