1. Zapisz w najprostrzej postaci
2. Rozwiaż równania
a) (2x+1) do kwadratu= 6+3x do kwadratu
b) (2x-5)(2x+5)=x-25
c) 10x-x do kwadratu =25
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1)
1-√5-(2√5-3)²=1-√5-(20+9-12√5)=1-√5-29+12√5=-28+11√5
2)
a)
(2x+1)²=6+3x²
4x²+1+4x=6+3x²
x²+4x-5=0
a=1
b=4
c=-5
Δ=16-4*1*(*-5)=36
x₁=(-4-6)/2=-5
x₂=(-4+6)/2=1
b)
(2x-5)(2x+5)=x-25
4x²-25=x-25
4x²-x=0
x(4x-1)=0
x₁=0
x₂=¼
c)
10x-x²=25
a=-1
b=10
c=-25
Δ=100-4*(-1)*(-25)=0
x₁=x₂=-10/(-2)=5