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i 12×1dm=12dm
Obkw= 4a
a=4dm ÷ 4= 1dm
zakladajac ze prostokat powstal po ulozeniu kwadratow jeden obok drugiego
Obpr=2a+2b
b=2×1dm + 2×5= 5dm
Obpr= 2dm + 10dm= 12dm