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9x +6 < 20 / -6
9x < 14 /:9
x< 14/9 ∧ 14/9 <2
x∈( -∞, 2)
Odp. B
Zad.2.
3/(x-3) - x/(x+1)= zał. x-3≠0 ⇒x≠3
x+1≠0⇒x≠-1
= 3(x+1)/ (x-3)(x+1) - x(x-3)/(x-3)(x+1)=
3(x+1)-x(x-3)/ (x-3)(x+1)= (3x +3-x²+3x)/(x-3)(x+1)=(-x²+6x +3)/(x² --2x -3)