1. Ułóż równania reakcji: C4H10 ---> RCl ---> ROH ---> kwas ---> maślan butylu
C₄H₁₀ + Cl₂ --hv--> C₄H₉Cl + HCl
C₄H₉Cl + NaOH --> C₄H₉OH + NaCl
C₄H₉OH + CuO --> C₃H₇CHO + Cu + H₂O
C₃H₇CHO + Ag₂O --> C₃H₇COOH + 2Ag
C₃H₇COOH + C₄H₉OH --> C₃H₇COOC₄H₉ + H₂O
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Litterarum radices amarae sunt, fructus iucundiores
Pozdrawiam :)
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C₄H₁₀ + Cl₂ --hv--> C₄H₉Cl + HCl
C₄H₉Cl + NaOH --> C₄H₉OH + NaCl
C₄H₉OH + CuO --> C₃H₇CHO + Cu + H₂O
C₃H₇CHO + Ag₂O --> C₃H₇COOH + 2Ag
C₃H₇COOH + C₄H₉OH --> C₃H₇COOC₄H₉ + H₂O
----------------------------------------------------------------------------------------------------
Litterarum radices amarae sunt, fructus iucundiores
Pozdrawiam :)