October 2018 1 33 Report
1) tentukan rumus empiris suatu senyawa yang memiliki karbon = 25,41%, hidrogen = 3,17% , oksigen = 37,56% klor!

[C = 12, H = 1, 0 = 16; Cl = 35,5] [C₂H₃O₂Cl]

2) hitung volume oksigen yang dibutuhkan untuk pembakaran sempurna dari 20 cm² propana (C₃H₈) !

C₃H₈ + 5O₂ ⇒ 3CO₂ + 4H₂O
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