1) rozwiąż równanie.
(x-2) (x+3) - (x+4)^2= -25
(x-2)(x+3) - (x+4)² = -25
x² + 3x -2x -6 -(x² + 8x + 16) = -25
x² - 5x - 6 - x² - 8x - 16 = -25
-13x = -3
x = 3/13
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Litterarum radices amarae sunt, fructus iucundiores
Pozdrawiam :)
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(x-2)(x+3) - (x+4)² = -25
x² + 3x -2x -6 -(x² + 8x + 16) = -25
x² - 5x - 6 - x² - 8x - 16 = -25
-13x = -3
x = 3/13
----------------------------------------------------------------------------------------------------
Litterarum radices amarae sunt, fructus iucundiores
Pozdrawiam :)