1. Rozwiąż równanie:
2. Rozwiąż nierówność:
Δ=b²-4ac
x₁=[-b-√Δ]/2a
x₂=[-b+√Δ]/2a
x₀=-b/2a
a]
√[x²-12x+36]=5 /²
x²-12x+36-25=0
x²-12x+11=0
Δ=144-44=100
x₁=[12-10]/2=1
x₂=[12+10]/2=11
b]
√[x²+4x+64]=8 /²
x²+4x+64-64=0
x(x+4)=0
x=0 lub x=-4
2a]
√[x²-4x+4]>5 /²
x²-4x+4-25=0
x²-4x-21=0
Δ=16+84=100
x₁=[4-10]/2=-3
x₂=[4+10]/2=7
x∈(-∞;-3) lub (7;+∞)
√[x²+20x+100]≤7 /²
x²+20x+100-49=0
x²+20x+51=0
Δ=400-204=196
x₁=[-20-14]/2=-17
x₂=[-20+14]/2=-3
x∈ <-17;-3>
odp w zalaczniku
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Δ=b²-4ac
x₁=[-b-√Δ]/2a
x₂=[-b+√Δ]/2a
x₀=-b/2a
a]
√[x²-12x+36]=5 /²
x²-12x+36-25=0
x²-12x+11=0
Δ=144-44=100
x₁=[12-10]/2=1
x₂=[12+10]/2=11
b]
√[x²+4x+64]=8 /²
x²+4x+64-64=0
x(x+4)=0
x=0 lub x=-4
2a]
√[x²-4x+4]>5 /²
x²-4x+4-25=0
x²-4x-21=0
Δ=16+84=100
x₁=[4-10]/2=-3
x₂=[4+10]/2=7
x∈(-∞;-3) lub (7;+∞)
b]
√[x²+20x+100]≤7 /²
x²+20x+100-49=0
x²+20x+51=0
Δ=400-204=196
x₁=[-20-14]/2=-17
x₂=[-20+14]/2=-3
x∈ <-17;-3>
odp w zalaczniku