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3^p + 1/3 3^p < 12
4/3 3^p < 12
3^p < 9
3^p < 3^2
p<2
Karena diatas sumbu x, dipastikan persamaan > 0
(1/3)^2 akar(3^(2x+1)) - 27 > 0
1/9 akar(3^(2x+1)) > 27
akar(3^(2x+1)) > 243 --> 3^(2x+1) > 243^2
3^(2x+1) > 3^10
2x+1 > 10 --> 2x > 9 --> x > 9/2
Baru inget...