Question

1. persamaan garis l yg tegak lurus dg garis q: 3x - 2y + 1 = 0 dan melewati A (-3,5 ) adalah...

Answer 1

Ax + by + c = 0
 3x - 2y + 1 = 0

a = 3
b = -2
c = 1

m₁ = -a/b
     = -3/-2
     = 3/2

 m₁ × m₂ = -1
3/2 × m₂ = -1
        m₂ = -2/3

y - y₁ = m(x - x₁)
 y - 5 = -2/3(x - (-3))
 y - 5 = -2/3(x + 3)
 y - 5 = -2/3x - 2
      y = -2/3x - 2 + 5
      y = -2/3x + 3
    3y = -2x + 9

Jadi persamaan garisnya adalah 3y = -2x + 9.