1.N2 + 3H2--->2NH31 mole N ----- 2 mole NH30,5 mola N ---- XX= 1 mol NH31 mol N2 wystarczy do otrzymania 0,2 mola NH3 2. 2Mg + O2--->2MgO 48g Mg - 2 mole MgO 12g Mg - X X=0,5 mola MgO 12 Mg wystarczy do otzrymania 0,5 mola MgO
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1.
N2 + 3H2--->2NH3
1 mole N ----- 2 mole NH3
0,5 mola N ---- X
X= 1 mol NH3
1 mol N2 wystarczy do otrzymania 0,2 mola NH3
2.
2Mg + O2--->2MgO
48g Mg - 2 mole MgO
12g Mg - X
X=0,5 mola MgO
12 Mg wystarczy do otzrymania 0,5 mola MgO