Question

1. oblicz 4(x-3)-(x+1)(x-1)=5(x-1)-(x+3)kwadratu -2

5(x-1)+3(x+2)(x-2)-2xkwadrat=x(6+x)

PILNE NA DZIS :)

Answer 1

4(x-3)-(x+1)(x-1)=5(x-1)-(x+3)^2 -2    ^2- kwadrat

4x-12-(x^2-1)=5x-5-x^2-6x-9-2

4x-12-x^2+1=-x-x^2-16

4x-11=-x-16

5x=-5

x=-1

 

b)

 

5(x-1)+3(x+2)(x-2)-2x^2=x(6+x)

5x-5+3(x^2-4)-2x^2=6x+x^2

5x-5+3x^2-12-2x^2=6x+x^2

5x-6x=17

-x=17

x=-17

 

Pozdrawiam

JiuJi

 

 

 

Answer 2

4(x-3)-(x+1)(x-1)=5(x-1)-(x+3)² -2

4x - 12 - x² + 1 = 5x - 5 - x² - 6x - 9 - 2

4x - 11 = - x - 16

4x + x = -16 + 11

5x = - 5

x = -1

 

 

5(x-1)+3(x+2)(x-2)-2x²=x(6+x)

5x - 5 + 3(x² - 4) - 2x² = 6x + x²

5x - 5 + 3x² - 12 - 2x² = 6x + x²

5x + x² - 17  = 6x + x²

5x - 6x = 17

-x = 17

x = -17