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a) C₂H₄ + H₂ + katalizator (Pt lub Ni) → C₂H₆
b) C₂H₄ + Cl₂ → C₂H₄Cl₂
c) C₂H₄ + HBr → C₂H₅Br
2.
wzór: C₂H₄
M węgla = 12 g/mol
M wodoru = 1 g/mol
M C₂H₄ = 2*12 g/mol + 4*1 g/mol = 24 g/mol + 4 g/mol = 28 g/mol
C : H
24 g/mol : 4 g/mol
6 : 1
odp. stosunek masy wegla do masy wodoru w czasteczce etenu wynosi 6:1.