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2HCl + CaO --> CaCl₂ + H₂O
HCl + KOH --> KCl + H₂O
2. MnO₂ +4HCl --> MnCl₂ + Cl₂ + 2H₂O
mHCl = 1g/mol + 35,5g/mol = 36,5 g/mol
4*36,5g HCl ---- 22,4 dm³ Cl₂
14,6g HCl --- x
4*36,5x = 14,6*22,4
x = 2,24 dm³ Cl₂
Pozdrawiam ;)
CaO + 2HCl = CaCl2 + H2O
KOH + HCl = KCl + H2O
2).
MnO2 + 4HCl = MnCl2 + Cl2 + 2H2O
mama kwasu = 14,6g
mole to: n=m/M => n=14,6/36,5 = 0,4 mola HCl,
to zgodnie z równaniem reakcji mamy z 1/4 mola Cl2 z 1 mola HCl
n=0,1 mola Cl2
to objetosc v=n*Vo => V=0,1*22,4 = 2,24 dm3