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odp b
2. x² + 3x + 2 = 0
Δ=b²-4ac=3²-4*1*2=9-8=1
x₁=-b+√Δ/2a=-3+1/2=-2/2=-1
x₂=-b-√Δ/2a=-3-1/2=-4/2=-2
odp d
:))
zad2
x²+3x+2=0
(-1)*(-1)+3(-1)+2=0
x=-1∨x=-2
x=-1 jest większą z tych liczb