1) jeżeli beta = 45 stopni to:
a) tg beta > sin beta
b) tg beta = sin beta
c) tg beta < sin beta
d) sin beta > cos beta
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odp. a
tg beta > sin beta
tg45st. = 1
sin45st. = √2/2
1 > √2/2
Sprawdzamy:
a) tgβ45=1
sinβ45= ≈0,7 czyli tgβ45>sinβ45
Dalej nie sprawdzamy odp A