1. Jednakowym literom odpowiada ta sama liczba.Wpisz brakujące liczby wiedząc, że: A+A+B+C=14 A+B+B+C=12 A+B+C+C=10 . NA TERAZ!
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2A+B+C= 14
A+2B+C= 12
A+B+2C= 10
4A+4B+4C= 36 /:4
A+B+C= 9
2A+B+C-A-B-C= 14-9
A= 5
A+2B+C-A-B-C= 12-9
B= 3
A+B+2C-A-B-C= 10-9
C= 1
I sposób
2A + B + C = 14
A + 2B + C = 12
A + B + 2C = 10
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4A + 4B + 4C = 36
4 · (A + B + c) = 36 /:4
A + B + C = 9
(2A + B + C) - (A + B + C) = 14 - (A + B + C)
2A + B + C - A - B - C = 14 - 9
A = 5
(A + 2B + C) - (A + B + C) = 12 - (A + B + C)
A + 2B + C - A - B - C = 12 - 9
B = 3
(A + B + 2C) - (A + B + C) = 10 - (A + B + C)
A + B + 2C - A - B - C = 10 - 9
C = 3
II sposób
Odp. A=5; B=3; C=1